Write a program, which will find all such numbers between m and n (both included) such that each digit of the number is an even number.
Input Format:
The first line contains value m and n separated by a comma.
Output Format:
The numbers obtained should be printed in a comma-separated sequence on a single line.
Constraints:
1000<=m<=9000
1000<=n<=9000
Answers
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Explanation:
Void main void
{
int m, n
m. n = input("enter the two numbers")
if (m > n)
{
if ( m %% 2 == 0)
i = m;
while (i < n)
{
print ( i )
i = i+2;
}
else
i = m+1;
while (i < n)
{
print ( i )
i = i+2;
}
else // when n>m
{
if ( n %% 2 == 0)
i = n;
while (i < m)
{
print ( i )
i = i+2;
}
else
i = n+1;
while (i < m)
{
print ( i )
i = i+2;
}
return
}
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