write a pythagoran triplet whose one number is 6
Answers
Answered by
3
2m=6
m=6/2
m=3
m2-1
3*3-1
9-1
8
M2+1
3*3+1
9+1
10
answer are 8,10
hope it will help you
m=6/2
m=3
m2-1
3*3-1
9-1
8
M2+1
3*3+1
9+1
10
answer are 8,10
hope it will help you
Answered by
2
We know that if any number is m, it's pythogorean triplet is 2m, m^2-1, m^2+1
In the question,2m is 6
Therefore, m = 3
thus, m^2-1= 3^2-1= 9-1= 8
&,m^2+1= 3^2+1= 9+1= 10
Thus, the required numbers are 6,8,10
HOPE THIS HELPS!!!!
PLEASE MARK AS BRAINLIEST ANSWER!!!!!
All the best!!!!!!!!!!!!!!!!!!!!!!!!
In the question,2m is 6
Therefore, m = 3
thus, m^2-1= 3^2-1= 9-1= 8
&,m^2+1= 3^2+1= 9+1= 10
Thus, the required numbers are 6,8,10
HOPE THIS HELPS!!!!
PLEASE MARK AS BRAINLIEST ANSWER!!!!!
All the best!!!!!!!!!!!!!!!!!!!!!!!!
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