Question

Write a Pythagoras triplet whose one member is 14​

Answer 1

Answer:

Let us assume 2 m=14 therefore m=7

Now m

2

+1=7

2

+1=49+1=50

And m

2

−1=7

2

−1=49−1=48

Test : 14

2

+48

2

=196+1304=2500=50

2

Hence the triplet is 14,48 and , 50 Answer

Step-by-step explanation:

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Answer 2

Answer:

As we know, we have Pythagorean

triplet 7, 24 anf 25. as,

(25)

2

=(7)

2

+(24)

2

→ So, For general Pythagorean triplet, we

have sides of positive number.

→ 25, 24 & 7 and (a) product as sides

Let side

AB

=24a

BC

=7a

where aϵz

+

So, AC

2

=AB

2

+BC

2

=(24a)

2

+(7a)

2

AC

2

=576a

2

+49a

2

AC

2

=625a

2

AC

=25a

So, For a = 2, we have, triplet

BC=7(2)=14

AB=24(2)=48

& AC=25(2)=50

Pythagorean triplet 14, 48 & 50.

Step-by-step explanation:

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