Question

Write a Pythagoras triplet whose one number is 17​

Answer 1

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$\implies$$\large\bf{\underline{\red{VERIFIED✔}}}$

or any natural number m > 1, 2 m, m2 -1, m2 + 1 forms a Pythagorean Triplet.

Let us take m2+1=17m2=16m=4

⇒ value of m is an integer

So, this case is possible.

So we have,

2×4,42-1, 42+1=8,15,17.

$\boxed{I \:Hope\: it's \:Helpful}$

Answer 2

Answer:

So, the Pythagoras triplet whose one number is 17 is =8,15,17.