write a pythagoras triplet whose one number is 3
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The Pythagorean triplet whose smallest no. is 3 is (3,4,5) because
by Pythagoras theorem,
3^2+4^=5^2
9+16=2
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For any natural number m > 1, 2m, m^{2} - 1 and m^{2} + 1 forms a Pythagorean triplet.
So if we take, m^{2} - 1 = 16
m^{2} = 16 + 1 = 17
But the value of m will not be an integer.
Now we take, m^{2} + 1 = 16
m^{2} = 16 - 1 = 15
but the value of m will not be an integer.
If we take 2m = 16
then m = 8
Then m^{2} -1 = 64 - 1 = 63 and m^{2} +1 = 64 + 1 = 65.
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