Math, asked by vineetdilip, 8 months ago

Write a Pythagorean tripet whose smallest member is 6, 14

Answers

Answered by rockrohit8401
2

Answer:

calculate it yourself and remember it

Answered by mk610112manoj
3

Step-by-step explanation:

1.) \: 6 \\ pythagorean \: triplet \: of \: 6 =

 \: if \: the \: given \: membe \: is \: even \\then \: the \:  pythagoeran \: triplet \:  =  \\ ( \: 2m \:   \:  \:  \: {m}^{2}-1 \:  \:  \:  \:  {m}^{2} + 1)

1.) \: 6 \\ pythagorean \: triplet  =  \\  2m = 6 \\ m =  \frac{6}{2} \\ m = 3 \\ next  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\ {m}^{2}-1 \\  =  {3}^{2}  - 1 \:  \:  \:  \:  \:  \\  = 9 - 1 \:  \:  \:  \:  \:  \:  \:  \\  = 8 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\ next \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  {m}^{2} + 1 \\  =  {3}^{2}  + 1 \:  \:  \:  \:  \: \\  =  9  + 1 \:  \:  \:  \:  \:  \:  \\  = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\ hencep \: pythagoeran \: triplet =  \\ (6 \:  \: 8  \:  and \: 10.)

please mark as brainlinlist.

Similar questions