Question

Write a Pythagorean triple whose one member is 8

Answer 1

$\huge\boxed{Answer}$

82=64

⇒  100−64=36

⇒  √36=6

⇒ √100=10

Let

Hypotenuse =10            [ Since its greater than 6 and 8  ]

Base =8 and 

Perpendicular =6

(Hypotenuse)2=(Perpendicular)2+(Base)2                [ Pythagoras theorem ]

⇒  (10)2=(6)2+(8)2

⇒  100=36+64

⇒  100=100

∴   Pythagorean triplet are 6,8,10

$\huge\mathfrak\red{itz\:jyotsana☺}$

Answer 2

Answer:

6,8,10 are Pythagoras triplet

Step-by-step explanation:

as

8²+6²

=64+36

=100

=10²

hence 6,8,10 are triplet