write a pythagorean triple whose one number is 16
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Answer:
Pythagorean Triplets:
if m²+n² = p².
For every natural number m>1,
we have (2m,m²-1,m²+1) as a Pythagorean Triplet.
m = 16,
2m= 2×16 = 32.
m²-1 = 16² - 1 = 256 -1 = 255.
m²+1 = 16²+1 = 256 +1 = 257.
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Refer the attachment above .
In the above solution ,
smallest member ( 2m ) = 16
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