Question

write a Pythagorean triple whose one number is 6​

Answer 1

Answer:

Let 2n = 6 ∴ n = 3

Now, n2 -1 = 32 - 1 = 8

and n2 +1 = 32 + 1 = 10

Thus the required Pythagorean triplet is 6,8,10.

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Answer 2

Step-by-step explanation:

Answer. 2m,m²-1,m²+1 forms a Pythagorean triplet. Therefore the triplets are 6,8 and 10.