Question

write a Pythagorean triplet if one number is 14

Answer 1

Pythagorean triplet has three numbers
2m , m^2-1 and m^2+1
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let 2m= 14
then m =14/2=7
so.
m^2-1= 7^2-1 = 49-1= 48
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and
m^2+1=7^2+1 = 49+1= 50
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.
so three numbers are.
14 , 48 and 50.
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Answer 2

hey dear

here is your answer

Solution

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to find pythagoran triplet

( 2m, m^2 -1. , m^2 +1 )

given number is 14

2m = 14

m. = 14 / 2

m = 7

so


m^2 = ( 7 ) ^2 -1

m^2 = 49 -1

m^2 = 49 - 1 = 48
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third triplet

m^2 +1 = 7

m^2 +1 = ( 7 )^2 +1

m^2 +1 = 7 ^2 +1

m^2 = 50

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so, pythagoran triplet is

( 14 , 48 , 50 )

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hope it helps

thank you