write a Pythagorean triplet if one number is 14
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Answered by
11
Hey,
Pythagorean triplets are of the form 2m,m²-1 and m²+1
Given one number,that is 14
14 can not be in the form of m²-1 or m²+1 as we get the following result.
m²-1=14
m²=13;m=√13
m²+1=14
m²=15;m=√15
So,it is of the form 2m
2m=14
m=7
So,the other Pythagorean triplets are of the form m²-1 and m²+1
m²-1=7²-1
=49-1=48
m²+1=7²+1
=49+1=50
So,the three Pythagorean triplets are 14,48 and 50.
HOPE IT HELPS:-))
Pythagorean triplets are of the form 2m,m²-1 and m²+1
Given one number,that is 14
14 can not be in the form of m²-1 or m²+1 as we get the following result.
m²-1=14
m²=13;m=√13
m²+1=14
m²=15;m=√15
So,it is of the form 2m
2m=14
m=7
So,the other Pythagorean triplets are of the form m²-1 and m²+1
m²-1=7²-1
=49-1=48
m²+1=7²+1
=49+1=50
So,the three Pythagorean triplets are 14,48 and 50.
HOPE IT HELPS:-))
Answered by
7
HeY mAtE heRe iS yoUr aNsWer ✍✍........
GivEn.....onE nuMbeR iS 14
FoRmulA - (2m )
( m²+1)
( m²-1 ).........
pUt tHe vaLuE 2m → 14 /2
→ 7 .....
knOw (m²+1) → (7²+1 )= (49 +1) = 50....
heRe.. (m²-1) → (7²-1)= (49-1) = 48......
so ,tHe thReE PythAgOreaN tRiplEt aRe 7 , 48 aNd 50.....
HoPe it wiLL helP yOu .... plZ maRk it As brANiliESt................
GivEn.....onE nuMbeR iS 14
FoRmulA - (2m )
( m²+1)
( m²-1 ).........
pUt tHe vaLuE 2m → 14 /2
→ 7 .....
knOw (m²+1) → (7²+1 )= (49 +1) = 50....
heRe.. (m²-1) → (7²-1)= (49-1) = 48......
so ,tHe thReE PythAgOreaN tRiplEt aRe 7 , 48 aNd 50.....
HoPe it wiLL helP yOu .... plZ maRk it As brANiliESt................
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