Question

Write a pythagorean triplet if one number is 16

Answer 1

For any natural no. M>1, we have
(2m)^2+(m^2-1)=(m^2+1). So, 2m,m^2-1,m^2+1 forms a pythagorean triplet.

Solution..

Let 16=2m
So m=8

m^2-1 = 8^2-1=64-1=63

m^2+1 = 8^2+1=64+1=65

Check

63^2+16^2=65^2
3969+256=4225
4225=4225

Hence, the triplets are 8, 64, 65.