Math, asked by prime38, 1 year ago

write a pythagorean triplet in which one no. is 14

samarth44o: hi

raju02468: there are 3 process of Pythagoras triplets . this is one of those , here one no' is 14 . the is 2m ,m2-1,m2+1 so 2m =14 , m = 7(14/7) . so m2-1 = (7)2-1=49-1=48 and m2+1 =(7)2+1=49+1=50 . Therefore the Pythagoras triplets are 14,48,50 Hope it is helpful

raju02468: formula of this Pythagoras triplets is 2m,m2-1and m2+1

Answers

Answered by Anonymous

Phythagorean triplets are numbers in form -

2m , m²+1 and m²-1

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So If one of the numbers is 14

let it be 2m.

Then, 2m = 14

or, m = 14/2

or, m= 7

We've got m = 7

So other two numbers are -

m²+1 = 7²+1 = 49+1 = 50

m²-1 = 7²-1 = 49-1 = 48

So, The triplets are 14,48 and

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