Question

write a Pythagorean triplet one of whose member is 11​

Answer 1

Answer:

Pyhtagorean triplet with one no. 11 is $\mathfrak\green{11,60,61}$.

PROOF:

11^2 = 121

60^2 = 3600

61^2 = 3721

121 + 3600 = 3721

Hence Proved.

Hope this helps you.

Answer 2

Answer:

11,29.25,31.25

Step-by-step explanation:

2m^2 +(m^2-1)^2=(m^2+1)^2

2m, m^2-1,m^2+1 form pythagorean pair..

2m=11

m=11/2=5.5

m^2-1=(11/2)^2-1

=(121/4)-1

=30.25-1=29.25

m^2+1=30.25+1=31.25

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