write a Pythagorean triplet where one number is 12
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Answered by
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.2m=12
m=12÷2=6
m^2+1
=6^2+1
=36+1
=37
m^2-1
=6^2-1
=36-1
=35
hope it is useful...
m=12÷2=6
m^2+1
=6^2+1
=36+1
=37
m^2-1
=6^2-1
=36-1
=35
hope it is useful...
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Answered by
3
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