write a Pythagorean triplet whose 1 number is 40
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One number is 40
Pythogorean triplets =2m,m^2+1,m^2-1
2m=40
M=40/2=20
M^2+1=20^2+1=401
M^2-1=20^2-1=399
(40 ,401,399)
Pythogorean triplets =2m,m^2+1,m^2-1
2m=40
M=40/2=20
M^2+1=20^2+1=401
M^2-1=20^2-1=399
(40 ,401,399)
asr7:
exactly
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0
A Pythagorean Triplet whose 1 number is 40 is 40,41 and 9.
Given:
One of the numbers of the Pythagorean triplet is 40.
To Find:
Pythagorean triplet whose one number is 40.
Solution:
- A Pythagorean triplet is a set of three numbers in which the sum of the square of two numbers is equal to the square of the third number like 3,4, and 5 where 3² + 4² = 5². The third number would be the greatest in magnitude.
- We can denote the length of sides of a Right-angled triangle by using the Pythagorean Triplet. Here we denote the length of the hypotenuse equal to the greatest number of the Pythagorean triplet.
- Going by the same concept we get the Pythagorean triplet whose one number is 40 as 40, 41, and 9 because 41² = 40² + 9². The sum of squares of 40 and 9 is equal to the square of 41.
Hence, the Pythagorean Triplet whose 1 number is 40 is 40,41, and 9.
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