Question

Write a Pythagorean triplet whose greatest member is 122

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Formula Used :

Pythagoras Triplet = 2m , m² - 1 , m² + 1

Required Solution :

Here,

Greatest number = m² + 1 = 122

→ m² + 1 = 122

→ m² = 122 - 1

→ m² = 121

→ m = √121

→ m = 11

If, m = 11

2m = 11 × 2 = 22

m² - 1 = ( 11 )² - 1 = 121 - 1 = 120

The required triplet are = 22 , 120 , 122

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