Question

Write a Pythagorean triplet whose largest member is the following.
a)26​

Answer 1

Step-by-step explanation:

Given largest number is 65. We know that 2m, m2 – 1, m2 + 1 form a Pythagorean triplet. let m2 + 1 = 65 m2 = 65 – 1 m2 = 64 m2 = 8 × 8 m = 8 ∴ 2m = 2 × 8 = 16 m2 – 1 = 64 – 1 = 63 ∴ The required Pythagorean triplet is (16, 63, 65) (ii) Smallest number is 10 We know that (2m, m2 – 1, m2 + 1) form a Pythagorean triplet. Given smallest number is 10 let 2m = 10 m = 102 m = 5 m2 + 1 = 52 + 1 = 25 + 1 = 26 m2 – 1 = 52 – 1 = 25 – 1 = 24 ∴ The required Pythagorean triplet is (10, 24, 26)Read more on Sarthaks.com - https://www.sarthaks.com/1005299/find-a-pythagorean-triplet-whose-i-largest-member-is-65-ii-smallest-member-is-10?show=1005301#a1005301