Question

write a Pythagorean triplet whose member are formed by given natural number 6

Answer 1

HII

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Let 2m = 6

m = 3

m²+ 1 = 3² + 1= 9 + 1 = 10

m²- 1 = 3 2 - 1 = 9 - 1 = 8

check:

6 ² + 8² = 36 + 64 = 100 = 10²

Hence, the triplet is 6, 8 & 10

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Hope it will help u.................

Answer 2

Answer:

answer is

Step-by-step explanation:

12.35.37.............