Write a Pythagorean triplet whose member is 14
Answers
Answered by
0
Answer:
14,48,50
Step-by-step explanation:
if 2m=14
m=7
m2-1=48
m2+1=50
Answered by
0
Answer:
it is of the form of 2n, n^2-1, n^2+1
2n= 2(7) = 14
n= 7
n^2-1= 7^2-1
= 49-1
= 48
n^2+1= 7^2+1
= 49+1
= 50
Therefore, the triplets are 14,48,50
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