Question

write a pythagorean triplet whose member is 80

Answer 1

hey here is ur answer

let the other number be x

\sqrt{ {80}^{2} + {x}^{2} }

√1600+x^2

I hope this helps you

Answer 2

Answer:

2m, m2 -1, m2+ 1

2m = 80

m = 80/2

m = 40

m2 -1 = 80

m2 = 80+1

m2 = 81

m2 + 1 = 80

m2 = 80- 1

m2 = 79

Pythagorean triplet are 80,81,79