Question

write a Pythagorean triplet,whose members are formed by 16.​

Answer 1

Answer:

We know the basic Pythagorean

triplet 3, 4 and 5.

Let us construct a triangle which have sides in a multiple of 3, 4 & 5.

here AB=3a

BC=4a

& let, get AC as 5a

From Pythagoras theorem

where aϵz

+

AC

2

=AB

2

+BC

2

=(3a)

2

+(4a)

2

=9a

2

+16a

2

AC

2

=25a

2

AC=5a

So, Let us put a = 4 we get

AB = 12, BC = 16 & AC = 20.

So, We have Pythagorean triplet:

12, 16 and 20.

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Answer 2

Answer:

63, 16 and 65 are one Pythagorean triplet. ∴ Consider m = 4 and n = 2.

Step-by-step explanation:

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