Question

Write a Pythagorean triplet whose members are formed by given natural number 8.

Answer 1

This is Your Answer...

Pythagoras triplets are of the form.

2m, m² -1 and m² + 1.

It is given that smallest number is 8.

So, 2m = 8.

m = 4.

Now, second number = m² -1 = 4² - 1 = 15.

and, third number = m² + 1 = 4² + 1 = 17.

Hence, the triplet is 8, 15 and 17.

Verification :-

17² = 8² + 15²

289 = 64 + 225

289 = 289.

Hence, proved.

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Answer 2

Answer:

here you go..

Step-by-step explanation:

as the question is "formed by natural number 8" so we understand that we have to take pythagorean triplet from number '8'

formula :- 2m, m²-1 , m²+1

let m be 8

2m=2×8=16

m²-1=8²-1 =64-1=63

m²+1=8²+1=64+1=65

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