Question

write a Pythagorean triplet whose no. one no. is 63​

Answer 1

$\huge\boxed{\fcolorbox{black}{blue}{Solution↴}}$

The given number is 63

➜We know that,

2m,m²+1,m²-1

Let m be 8

So, 2m =2×8=16

m²+1-8²+1=65

m²-1-8²-1= 63

➜ So, the no. is = 8,65,63.