Write a Pythagorean triplet whose one member 6.
Answers
Answered by
0
Answer:
formula for Pythagorean triplet = m^2-1, 2m, m^2 +1
ATQ
Let ,2m be 6,
So, m = 3
m^2-1 = 3^2
=9 -1
=8
m^2+1=3^2+1
=9+1
= 10
Hence, Pythagorean triplet with a member 6 is 6,8,10
( 6^2+8^2= 36+64
= 100= 10^2)
Answered by
0
Step-by-step explanation:
formula of Pythagorean triplet
= 2m , m²-1 , m²+1
according to question
m= 6
2m = 2× 6 = 12
m²-1= 6²-1 = 36 -1 = 35
m²+1 = 6²+1 = 36 + 1 = 37
hence, the Pythagorean triplet = 12 , 35 , 37
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