write a pythagorean triplet whose one member is 14.
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Step-by-step explanation:
2m, m² - 1 and m² + 1 are the 3 pythagorean triplets form
Pythagorean triplets are of the form 2m,m²-1 and m²+1
Given one number,that is 14
14 can not be in the form of m²-1 or m²+1 as we get the following result.
m²-1=14
m²=13;m=√13
m²+1=14
m²=15;m=√15
So 14 is of the form 2m
2m=14
m=7
Remaining Pythagorean triplets are of the form m²-1 and m²+1
m²-1=7²-1
=49-1=48
m²+1=7²+1
=49+1=50
So, the three Pythagorean triplets are 14,48 and 50.
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