Question

write a Pythagorean triplet whose one member is 14

Answer 1

Let  2 m = 14

 m = 7

 m² + 1 = 7²+ 1 = 49 + 1 = 50


m²- 1 = 7² - 1 = 49 - 1 = 48

Answer 2

2n=14
n=7
n square - 1 = 7 square - 1 = 49 - 1 = 48
n square + 1 = 49 + 1 =50
Thus, the Pythagorean triplet is 14,48 and 50