Question

write a pythagorean triplet whose one member is 14​

Answer 1

Phythagorean triplets are numbers in form -

2m , m²+1 and m²-1

=========================================

So If one of the numbers is 14

let it be 2m.

Then, 2m = 14

or, m = 14/2

or, m= 7

We've got m = 7

So other two numbers are -

m²+1 = 7²+1 = 49+1 = 50

m²-1 = 7²-1 = 49-1 = 48

So, The triplets are 14,48 and 50

Answer 2

Answer:

Step-by-step explanation:

2m= 14

m=14/2

m=7

   

m²+1= 7²+1= 49+1= 50

m²- 1= 7²-1= 49-1 = 48

therefore, the triplets are 14, 48 and 50

Hope this was something that u were looking for