Question

write a pythagorean triplet whose one member is 16, how to do ??

Answer 1

2m=16
m=16\2
= 8.

m^2=8.
so,8^2=64.

now using the formula
m^2 - 1
since m^2 is 8
8^2-1
64 - 1=
63.

m^2 + 1
64 + 1 =
65.

Therefore, the Pythagorean triplets are 16,63,65.

Answer 2

Step-by-step explanation:

Pythagorean triplet

three natural numbers m,n and p are said to form a pythagorean triplet ( m,n,p) ,

if m²+n²=p²

for every natural number m>1,

we have (2m,m²-1,m²+1) as a pythagorean triplet

here,

m=16

2m=2×16=32

m²-1=16²-1=256-1= 255

m²+1=16²+1=256+1=257

therefore,

Required pythagorean triplet

(32,255,257)