Write a Pythagorean triplet whose one member is 22
Answers
Answered by
118
As we know the formula to find pythogorean triplets is 2m,m×m+1,m×m-1. So lets assume 22 as 2m ..so 22=2m
m=22÷2
m=11
m×m-1 = 11×11-1 = 120
m×m+1=11×11+1=122
So the pythogorean triplet is 22,120,122
Answered by
27
Answer:
the numbers which form pyth.triplets are in 2n,n²+1,n²-1
hence 2n=22
n=22/2=11
2n=11
n²-1=11²-1=121-1=120
n²+1=11²+1=121+1=122
11,120,122
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