Question

Write a Pythagorean triplet whose one member is 26

Answer 1

Answer:

Step-by-step explanation:

Triplets are in the form 2m, m^2-1, m^2+1

2m=26, So, m=26/2 =13

m^2-1= 13^2-1=169-1=168

m^2+1=13^2+1=169+1=170

Triplets are: 26, 168, 170

Answer 2

The required Pythagorean triplet is 26, 168, 170.

Given,

A number 26.

To Find,

A Pythagorean triplet whose one member is 26.

Solution,

Since we know that the Pythagorean triplets are in the form 2m, m²-1, m²+1

Now, it is given that one of the members of the triplet is 26.

So, we will compare it with 2m.

2m=26, So, m=26/2 =13

Now, substituting the value of m in m²-1.

m²-1= 13²-1=169-1=168

Now, substituting the value of m in m²+1.

m²+1=13²+1=169+1=170

Hence, the required Pythagorean triplet is 26, 168, 170.

#SPJ3