Question

write a pythagorean triplet whose one member is 28 formula 2n(n-1),(n+1)​

Answer 1

Answer:

28 , 195 , 197

Step-by-step explanation:

Formula - 2n , n²- 1 , n² + 1

2n = 28

n = 14

n² = 196

(2 × 14) , (14²-1) , (14²+1)

28 , 196-1 , 196 + 1

$14 \times 14 = 196$

Pythagorean Triplet = 28, 195 , 197