Question

write a pythagorean triplet whose one member is 32

Answer 1

Answer:32,24 and 40

Step-by-step explanation:

Answer 2

$\underline {\pink{ Pythagorean \: Triplet : }}$

$Three \: natural \: numbers \: m,n \:and \: p$

$are \:said \: to \: form \: a \: Phythagorean$

$(m,n,p) ,if \: m^{2} + n^{2} = p^{2}$

$\blue { For \: every \: number \:m \gt 1 , we }$

$\blue {have \: (2m,m^{2} - 1 , m^{2} + 1 ) \:as }$

$\blue { a \: Phythagorean \: Triplet }$

$Here \: 2m = 32$

$i ) \implies m = \frac{32}{2} = 16 \: --(1)$

$ii )m^{2} - 1 = 16^{2} - 1$

$= 256 - 1$

$= 255 \: --(2)$

$iii )m^{2} + 1 = 16^{2} + 1$

$= 256 + 1$

$= 257 \: --(3)$

Therefore.,

$\red{ Required \: Phythagorean \: Triplet }$

$\green { ( 32, 255, 257 )}$

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