Question

write a pythagorean triplet whose one member is 6​

Answer 1

Answer:

(i) Let 2n = 6 ∴ n = 3

Now, n2 -1 = 32 - 1 = 8

and n2 +1 = 32 + 1 = 10

Thus the required Pythagorean triplet is 6,8,10.

Step-by-step explanation:

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