Question

write a Pythagorean triplet whose one member is 6??? need solution with easy way...?

Answer 1

Heya!
--------

========================================================

▪A Pythagorean Triplet Consists of three members such that the Square of the largest member is equal to the Sum of Square of the other two members . This can be written as ,


a² = b² + c²



▪The Members of a Pythagorean Triplet are represented by -

=> 2m , m² - 1 and m² + 1


===============================


◾Here , 2m = 6


=> m = 3 ✔



=> m² - 1


=> (3)² - 1


=> 8 ✔



=> m² + 1

=> (3)² + 1

=> 10✔



⭐Hence the Member are 6 , 8 and 10 .


$..$
=========================================================

Answer 2

We know that the other members like this

6² = h² (hypotenuse square) - b² (any variable)    [note:h² comes first because hypotenuse is always the biggest among these three]

36 = (h+b) (h-b)

36 = 36 x 2  ( if a is odd, we take h- b = 1, & if a is even h-b is taken 2)

Now, since h- b = 2 , so h & b are alternate consecutive numbers.

so the triplets are alternate consecutive numbers which means that they leave a gap of one number

so  the order goes like

6-8-10 (here they are leaving 7 and 9)

checking

6² + 8² = 10²

36 + 64 = 100

HOPE THIS HELPS

pls mark as brainliest