Question

Write a Pythagorean triplet whose one member is 7

Answer 1

Answer:

14, 48 and 50.

Step-by-step explanation:

Since the formula for Pythagorean Triplets is: 2m, m²-1 and m²+1, we need to substitute 7 in the place of m.

This will give us,

                           2(7), 7²-1 and 7²+ 1

                           14, 48 and 50

Thus the required Pythagorean Triplets are 14, 48 and 50.

Hope this helps you :)

Answer 2

Answer:

$\huge\color{FCE205}\mathbb{ANSWER}$

Step-by-step explanation:

As we know That 2m,${m}^{2}$+1 and ${m}^{2}$-1 from a Pythagoras Triplet gor any number ,m > 1 .

Let assume 2m = 7

Therefore,m = $\frac{7}{2}$ = 3.5

And, ${m}^{2}$ + 1

= ${3.5}^{2}$ + 1

= 12.25 + 1

= 13.25

And, ${m}^{2}$ - 1

= ${3.5}^{2}$ - 1

= 12.25 - 1

= 11.25

Test = ${(7)}^{2}$ + ${(11.25)}^{2}$=${(13.25)}^{2}$

=> 49 + 126.5625 + 175.5625

Hence, Pythagoras Triplet with 7 as a number 7 is 7,11.25 and 13.25

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