Question

write a pythagorean triplet whose one member is 8​

Answer 1

Question:-

Write a Pythagorean triplet in which one number is 8

Solution:-

In a right angle triangle if

${(side)}^{2} + {(side)}^{2} = {(hypotenuse)}^{2}$

Then, the numbers are called Pythagorean triplet

Example:-

1) 6 , 8 and 10 are Pythagorean triplet

${6}^{2} + {8}^{2} = {10}^{2}$

$36 + 64 = 100$

$100 = 100$

2) 8 , 15 and 17 are Pythagorean triplet

${8}^{2} + {15}^{2} = {17}^{2}$

$64 + 225 = 289$

$289 = 289$

Final answer:-

$6 \: , 8 \: \: and \: \: 10$

$8\: , 15 \: \: and \: \: 17$

Answer 2

Answer:

6,8,10

Step-by-step explanation:

√(6^2 + 8^2) = 10

a pythagorean triplet whose one member is 8 is

6,8,10