Question

write a Pythagorean triplet whose one member is 8​

Answer 1

Answer:

the Pythagorean triplet whose one member is 8 are :8,15 and17.

Answer 2

In context to question asked,

We have to determine the value of Pythagorean triplet.

As per question,

One member of the triplet is 8.

So,

$8^{2}=64 \\\Rightarrow 100-64=36 \\\Rightarrow \sqrt{36}=6 \\\Rightarrow \sqrt{100}=10$

Let the value of Hypotenuse = 10,

base = 8 and Perpendicular = 6.

We are taking hypotenuse as 10 as we know that, the value of hypotenuse must be greater than base and perpendicular.

So,

$\text { Perpendicular }=6 \\(\text { Hypotenuse })^{2}=(\text { Perpendicular })^{2}+(\text { Base })^{2} \quad \text { [Pythagoras theorem ] } \\\Rightarrow(10)^{2}=(6)^{2}+(8)^{2} \\\Rightarrow 100=36+64 \\\Rightarrow 100=100 \\\therefore \text { Pythagorean triplet are } 6,8,10$

Hence, value of Pythagorean triplet will be 6,8, 10