Question

Write a Pythagorean triplet whose one member is 8.
i) 8,15,17 ii) (8,17,20) iii) (8,10,15) iv) 8,9,17​

Answer 1

Answer:

i) 8,15,17

Step-by-step explanation:

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Answer 2

Answer:

1. Now, second number = m² -1 = 4² - 1 = 15. and, third number = m² + 1 = 4² + 1 = 17. Hence, the triplet is 8, 15 and 17. 289 = 289.
2. Don't know
3. We get the Pythagorean triplets by using the General Formula that is [ 2m, m² - 1, n² + 1 ]

First let's take → m² - 1 = 8

→ m² = 8 + 1 = 9

→ m = 3

→ 2m = 6 and m² + 1 = 10

The triplet is therefore 6, 8, 10. hence, 8 is not the smallest method of this.

→ 2m = 8

→ m = 4

→ m² - 1 = 16 - 1 = 15 and

→ m² + 1 = 16 + 1 = 17

4. Don't know

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