write a Pythagorean triplet whose one member is 8 With steps and explanation
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For any natural number m > 1, we have (2m) ² + (m² – 1)²= (m² + 1)² . So, 2m, m² – 1 and m² + 1 forms a Pythagorean triplet.
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- 2m=8
- m =4
- m²=16
m²-1=16-1=15
m²+1=16+1=17
8²+15²=17²
64+225=289
hence the triplet is 8,15,17
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