Question

write a Pythagorean triplet whose one member is 8 With steps and explanation

Answer 1

For any natural number m > 1, we have (2m) ² + (m² – 1)²= (m² + 1)² . So, 2m, m² – 1 and m² + 1 forms a Pythagorean triplet.

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• 2m=8
• m =4
• m²=16

m²-1=16-1=15

m²+1=16+1=17

8²+15²=17²

64+225=289

hence the triplet is 8,15,17