Question

Write a Pythagorean triplet whose one member is
(i) 6
(ii) 14
(iii)16
(iv)18​

Answer 1

Step-by-step explanation:

(i) 6

let 2n = 6 n = 3

n² - 1 = 3² - 1 = 8

n² + 1 = 3² + 1 = 10

Thus the required Pythagorean triplet is 6,8,10 .

(ii) 14

let 2n = 14 n = 7

n² - 1 = 7² - 1 = 48

n² + 1= 7² + 1 = 50

Thus the required Pythagorean triplet is 14,48,50.

(iii) 16

let 2n = 16 n = 8

n² - 1 = 8² - 1 = 63

n² + 1 = 8² + 1 = 65

Thus the required Pythagorean triplet is 16,63,65.

(iv) 18

let 2n = 18 n = 9

n² - 1 = 9² - 1 = 80

n² + 1 = 9² + 1 = 82

Thus the required Pythagorean triplet is 18,80,82.

I hope it is help you ...