Question

Write a pythagorean triplet whose one member is


i). 6
ii). 14
iii) 16
iv).18

please full expain with answer​

Answer 1

Answer:

6

Step-by-step explanation:

Pythagorean triplets works as a square multiplied by b square = c square

Answer 2

Answer:

i) 6,8 and 10

ii) 14, 48 and 50

iii) 16, 63 and 65

iv) 18, 80, 82

Step-by-step explanation:

to find a Pythagorean triplet: 2m, $m^{2}$+1, $m^{2}$-1

i) 2m=6

=> m= 6/2

=> m=3

$=m^2 -1\\=(3)^2 -1\\=9-1\\=8\\\\=m^2+1\\=(3)^2+1\\= 9+1\\=10$

=>2m=2(3)

=2m=6

ii) 2m=14

=> m=7

$=m^{2}-1\\ =7^{2}-1\\=49-1\\=48$

$=m^{2}+1 \\=7^{2}+1\\=49+1\\=50$

=>2m=14

iii) 2m=16

=> m= 8

$=m^{2}+1 \\=8^{2}+1\\=64+1\\=65$

$=m^{2}-1 \\=8^{2}-1\\=64-1\\=63$

iv) 2m=18

=> m=9

$=m^{2}-1 \\=9^{2}-1\\=81-1\\=80$

$=m^{2}+1 \\=9^{2}+1\\=81+1\\=82$