Write a Pythagorean triplet whose one member is: (i) 6 (ii) 18
plz explain the steps...
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Answer:
1)
2m = 6
m=3
m²+1 = 3²+1
=9+1
=10
m²-1 =3²-1
= 8
Pythagoras triplet =6,8,10
2)
2m = 18
m=9
m²+1= 9²+1
82
m²-1= 9²-1
= 80
pythogeron triplet = 18,80,82
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