Question

write a Pythagorean triplet whose one no is 63

Answer 1

m^2-1=63
m^2=63+1
m=under root 64=8
2m =16
m^2-1=63
m^2+1=65
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Answer 2

THE GÎvĒÑ ÑØ ÎS = 63

WË KΠØW THÂT

2m,m²+1,m²-1

LET m be =8

2m =2*8=16

m²+1=8²+1= 65

m²-1=8²-1= 63

♦

♦ ♦ the no. is = 8,65,63.

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