Question

Write a Pythagorean triplet whose one number is 14 16 18

Answer 1

HEY ❤️ ❤️

$2n = 14 \\ \\ n = 7 \\ \\ {n}^{2} - 1 = {7}^{2} - 1 \\ = 48 \\ \\ {n}^{2} + 1 = {7}^{2} + 1 \\ = 50$




SO THE TRIPLETS ARE: 14, 48,50

$2n = 16 \\ \\ n = 8 \\ \\ {n}^{2} - 1 = {8}^{2} - 1 \\ = 63 \\ \\ {n}^{2} + 1 = {8}^{2} + 1 \\ = 65$



SO THE TRIPLETS ARE :16,63,65

$2n = 18 \\ \\ n = 9 \\ \\ {n}^{2} - 1 = {9}^{2} - 1 \\ = 80 \\ \\ {n}^{2} + 1 = {9}^{2} + 1 \\ = 82$


SO THE TRIPLETS ARE :18,80,82