Question

write a Pythagorean triplet whose one number is 14
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Answer 1

Answer:

Hence the square of the largest number is equal to the sum of the squares of remaining two numbers. Therefore ( 14, 48, 50) is a Pythagorean triplet

Answer 2

Answer:

(14.48,50)

Step-by-step explanation:

the members of a triplet are

2m, (m^2) - 1 and (m^2) + 1

if we take

m^2 + 1 = 14

then m^2 = 15

or if we take m^2 - 1 = 14 => m^2 = 13

as these aren't natural no values, 14 can't be equal to m^2 + 1 or m^2 - 1

so 14 = 2m

m = 7

then,

m^2 - 1 = 49 - 1 = 48

m^2 + 1 = 49 + 1 = 50

hence,

14, 48, 50