Question

write a Pythagorean triplet whose one number is 18

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Answer 1

Answer:

your answer is here

Step-by-step explanation:

(2m)²,(m²-1)²,(m²+1)²

Answer 2

Answer:

We have pythagorean triplet (2n,n

2

−1,n

2

+1) where n>1 (natural number)

Let n

2

−1=18

n

2

=19

n=

19

(not an integer)

n

2

+1=18

n

2

=18−1

n

2

=17

n=

17

(is not an integer)

So, let us take 2n=18

n=9

∴ The required triplet is (an integer)

(18,9

2

−1,9

2

+1)=(18,81−1,81+1)

i.e., (18,80,82)