Question

write a pythagorean triplet whose one number is 6

Answer 1

hey mate..hope it helps u

Answer 2

Step-by-step explanation:

let 2n =6 n =6

Now n

${n}^{2} - 1 = 3 { - 1}^{2} = 8$

now

$n {}^{2} + 1 = 3 {}^{2} + 1 = 10$

rhus the required Pythagorean triplets number is 6,8,10

plz mark brainalist