Question

Write a Pythagorean triplet whose one number is 8

Answer 1

Let 2n = 8

then n = 4

Therefore n^2 + 1 = 16+1 = 17

n^2-1 = 15

therefore the answer is 17,16 & 8

$...$

Answer 2

Answer:

$we \: know \: that$

PYTHAGOREAN TRIPLET NUMBER

$2m \: \: \: m {}^{2} - 1 \: \: m {}^{2} + 1$

M= 8

$2 \times 8 \: \: 8 {}^{2} - 1 \: \: 8 {}^{2} + 1$

$16 \: \: \: 64 - 1 \: \: \: 64 + 1$

$16 \: \: 63 \: \: 65 \: \: answer$

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