write a Pythagorean triplet whose one number is 8
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second number = m² -1 = 4² - 1 = 15. and, third number = m² + 1 = 4² + 1 = 17. Hence, the triplet is 8, 15 and 17. 289 = 289.
Step-by-step explanation:
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Answer:
6,8,10
Step-by-step explanation:
LET A = 6
LET B = 8
LET C = 10
A^2+B^2= C^2
36+64=100
100=100
LHS =RHS
THEREFORE PYTHAGOREAN TRIPLET IS 6,8,10
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